first fundamental theorem of calculus
the first fundamental theorem of calculus states that (just trying to remember here), with f(x) being the antiderivative of f(x), while u stand for the upper bound and l stands for the lower bound, the definite integral of a function f(x) is equal to f(u) – f(l).
“solve the integral from 2 to 3 of x^2” well, this should be easy. just use the first fundamental theorem of calculus.
the antiderivative of x^2 = (x^3)/3. (3^3)/3 = 9, and (2^3)/3 = 8/3. 9 – 8/3 = 19/3, which is equal to 6.3333333… time to search this up on good ol’ wolfram alpha. *checks* alright!
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